最小公倍数和最大公约数

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long long com_mul(long long n1,long long n2)
{
	long long ans=n1*n2;
	long long i=2,limit=sqrt((double)min(n1,n2))+1;
	while(i<=n1&&i<=n2&&i<=limit)
	{
		if(n1%i==0&&n2%i==0)
		{
			ans/=i;
			n1/=i;
			n2/=i;
		}
		else
			i++;
	}
	return ans;
}

long long com_factor(long long n1,long long n2)
{
	long long ans=1;
	long long i=2,limit=sqrt((double)min(n1,n2))+1;
	while(i<=n1&&i<=n2&&i<=limit)
	{
		if(n1%i==0&&n2%i==0)
		{
			ans*=i;
			n1/=i;
			n2/=i;
		}
		else 
			i++;
	}
	return ans;
}